Question

Assuming the density of air to be 1.295 kg/m³ ,find the fall in barometric height in mm of Hg at a height of 107 m above sea level . Take density of mercury=13.6×10³kg/m³​

Answer 1

Answer:

ρ = 1.295 kg/m³

decrease in the pressure of air = ρ g h = 1.295 * g * 107  Pa

ρ g h = 13.6 * 10³ * g * H

H = decrease in barometric height of mercury

   = ρ g h / (13.6*10³ * g) = 10.188 mm

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Answer 2

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