assuming the length of a chain to be L and coefficient of static friction Mu, compute the maximum length of the chain which can be held outside a table without slipping.
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Answer:x=u÷u+1×L
where,u=coefficient of static friction
Explanation:
Let the total length of chain be L
Length of portion hanging be x
Remaining part=L-x
Whenever we use the concepts of objects like chain or rod whose linear mass densities are constant we should use the concept of mass gradient i.e M/L
F=mg=M/L×g
Since the gravitational force and normal force cancel out each other we balance the horizontal forces
Frictional force=gravitational force on hanging part
u×(M/L)×(L-x)×g=(M/L)×g
x=(u/u+1)L
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