Question

Astronaut at rest has heart rate of 65 beats/min. When astronaut's spaceship has moved at speed of 0.6c . Her heart rate as meausuerd by earth observer will be?

Answer 1

The formulae is as follows :

Rate = 1 {1/rate / √(1 - v²/c²)

Doing the substitution :

= 1/{1/65 / √(1 - 0.6²)

= 1/{0.015385 / 0.8)

= 1/0.019231

= 51.999

= 51.999 beats per minute