At 0°c and one atm pressure a gas occupies 100cc if pressure is increased to one and a half time and temperature is increased to one third of absolute temperature then final volume of gas will ne?
Answers
Answer: The correct answer is 88.8 cc.
Explanation:
From the ideal gas equation,
Here, are the initial and final volumes,
are the initial and final temperatures and
are the initial and final pressure.
It is given in the problem that ,
Calculate the final temperature.
Put .
Calculate the final volume of gas.
Put ,
,
,
and
in the above expression.
Therefore, the final volume of gas is 88.8 cc.
Explanation:
Answer: The correct answer is 88.8 cc.
Explanation:
From the ideal gas equation,
\frac{P_{1}V_{1}}{T_{1}} =\frac{P_{2}V_{2}}{T_{2}}
T
1
P
1
V
1
=
T
2
P
2
V
2
Here, V_{1},V_{2}} are the initial and final volumes, T_{1},T_{2}T
1
,T
2
are the initial and final temperatures and P_{1},P_{2}} are the initial and final pressure.
It is given in the problem that T_{1}= 0 degree Celsius= 273 KT
1
=0degreeCelsius=273K ,
Calculate the final temperature.
T_{2}=T_{1}+\frac{2}{3}T_{1}T
2
=T
1
+
3
2
T
1
T_{2}=\frac{4}{3}T_{1}T
2
=
3
4
T
1
Put T_{1}= 273 KT
1
=273K .
T_{2}=364 KT
2
=364K
Calculate the final volume of gas.
\frac{P_{1}V_{1}}{T_{1}} =\frac{P_{2}V_{2}}{T_{2}}
T
1
P
1
V
1
=
T
2
P
2
V
2
Put T_{1}= 273 KT
1
=273K , T_{2}=364 KT
2
=364K , V_{1}=100 ccV
1
=100cc , P_{1}=1 atmP
1
=1atm and P_{2}=\frac{3}{2}P_{1}P
2
=
2
3
P
1
in the above expression.
\frac{(1)(100)}{273} =\frac{(\frac{3}{2}(1))V_{2}}{364}
273
(1)(100)
=
364
(
2
3
(1))V
2
V_{2}=88.8 ccV
2
=88.8cc
Therefore, the final volume of gas is 88.8 cc.