Question

father's age is 25 years more than the son’s age. four years hence, father’s age will become 1 year less than thrice the son's age. what is father's present age?

Answer 1

Son's age  =x

Father's age = x + 25

after 4 years son's age = x + 4

after 4 years Father's age = x + 29 or 3(x+4) - 1

x + 29  =  3x + 12 - 1

2x = 29 -11

x = 18/2 = 9

Father's present age = 9 + 25 = 34years

Answer 2

The present age of the father is 34 years.

Step-by-step explanation:

• Let the age of the father $= x$ years
• So, the age of the son $= (x-25)$ (SInce father's age is 25 years more than the son's age)

After four years,

• Father's age would be $= (x+ 4)$

• and son's age would be $= (x-25) + 4 = (x-21)$

It is given that after four years, the father's age would become 1 year less than thrice the son's age.

Thus,

$3(x-21) -(x+4) = 1$

$3x -63 -x - 4 = 1$

$2x - 67 = 1$

$2x = 1+67$

$2x = 68$

$x = 34$

Hence, the age of the father at present is 34 years.