Question

father’s age is 3 times the sum of ages of his two children. after 5 years his age will be twice the sum of ages of two children. find the father.

Answer 1

Let the ages of 2 childrens be x years

Fathers age = 3x

Sum of the ages of 2 children after 5 years = x + 10

Fathers age after 5 yrs = 2(x + 10)



A/q,

3x + 5 = 2(x + 10)

3x + 5 = 2x + 20

3x - 2x = 20 - 5

x = 15



$\star{}$ Fathers present age => 3x => 3 × 15 => $\boxed{ \boxed{ \color{Blue}{45 \: years}}}$

Answer 2

Answer :

Given,

Father's age is 3 times the sum of ages of his two children.

After 5 years his age will be twice the sum of ages of two children.

To find,

present age of father

Solution :

Let the sum of ages of his two children be x.

ATQ,

His age is 3x

After 5 years,

Father's age = 3x + 5

Children's age = x + 5× 2 ( twice of five as there are two child's )

                       = x + 10

ATQ,

3x + 5 = 2(x + 10 )

3x + 5 = 2x + 20

This is a linear equation in one variable i.e x.

Solving this linear equation using transposition :

3x - 2x = 20 - 5

x = 15 years

So,

Father's present age = 3x = 3× 15 = 45 years.