Question

At 1:00 PM, one bus leaves anadpur to Shivnagar which is 225 km aprt and travels at an average speed of 45 km/hour. At the same time another bus leaves Shivnagar towards Anandpur at an average speed of 40 km/hour.. Find when and where will they cross each other?

Answer 1

AT 1:00PM
=One bus leave
ANANDPUR to shivnagar
One bus leave average =45km/h
second bus leave average =40km/h
=Let the time =x
= time=45+
×t+40×t=225
= 85t=225
= t=3 hour
=1:00-4:00 PM
=anandpur speed to reach 4:00PM
=distance =time×speed
=d=3×45
=135 km away from anandpur

Answer 2

Answer:

Step-by-step explanation: