Question

at 100g sample of water at 25C° and 1 atm of pressure? then 100g of water that has recently been heated to 100° c from 0° C and then cooled to 25° C 1 atm of pressure?​

Answer 1

Answer:

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Lumen

Physics

Heat and Heat Transfer Methods

Temperature Change and Heat Capacity

LEARNING OBJECTIVES

By the end of this section, you

Solution

Because water is in thermal contact with the aluminum, the pan and the water are at the same temperature.

Calculate the temperature difference:

ΔT = Tf − Ti = 60.0

Solution

Use the equation for heat transfer Q = mcΔT to express the heat lost by the aluminum pan in terms of the mass of the pan, the specific heat of aluminum, the initial temperature of the pan, and the final temperature: Qhot = mAlcAl(Tf − 150ºC).

Express the heat gained by the water in terms of the mass of the water, the specific heat of water, the initial temperature of the water and the final temperature: Qcold = mWcW(Tf − 20.0ºC).

Note that Qhot<0 and Qcold>0 and that they must sum to ze