Question

At 127°C temperature the volume of O2 gas is 3 litre. At which temperature the volume of O2 gas
will be halved

Answer 1

Answer:

Density P=1.5g/L        (P=M/V)⇒V=(M/P)

Temp.T=127  

0

c=400k

a=4atmL  

2

mol  

−2

    b=0.4L/mol

By vander waal's gas equation,

[P+  

V  

2

 

n  

2

 

​  

a](V−nb)=nRT                                 (assume 1 mole ⇒n=1)

⇒[P+  

(32/1.6)  

2

 

1

​  

(4)](  

1.6

32

​  

−(1)(0.4))          Mass of O  

2

​  

=32

=1×0.08×400

⇒[P+0.01](19.6)=32

⇒P+0.01=1.6326⇒P=1.6227atm

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Explanation:

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