Question

at 127c heat of fusion of a compound is 4.8 kjo /mol.Entropy change forprocess

Answer 1

temperature , T =127°C

we know, relation between Celsius and Kelvin.
K = 273 + C
so, temperature in Kelvin,T = 127 + 273 = 400K

heat of fusion, H = 4.8kJ/mol = 4800J/mol

entropy is the ratio of heat to the temperature.
so, S = H/T

S = 4800/400 = 12 j/mol/K