Question

At 143 K, the reaction of XeF₄ with O₂ F₂ produces xenon compound Y. The total number of lone Pair(s) of
electrons present on the whole molecule of Y is ………

Answer 1

XeF4+O2F2→(Y)XeF6+O2.

XeF6 contains 3 lp on each F and 1 lp on Xe.

Therefore, total number of lone pairs in molecule Y =3×6+1=19

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