Question

At 1pm one bus leaves Anandpur to shivnagar which is 255 km apart and travels at an average speed of 45km/hour.At the same time another bus leaves shivnagar towards anandpur at an average speed of 40 km/hour.find when and where will they cross each other?

Answer 1

Questioñ:

At 1.00 p.m,one bus leaves Anandpur to Shivnagar which is 255 km apart and travels at an average speed of 45 kilometre per hour. At the same time another bus leaves shivnagar towards Anandpur at an average speed of 40 kilometre per hour. Find when and where will they cross each other ?

Solutioñ:

AT 1:00PM

• One bus leave ANANDPUR to shivnagar

• One bus leave average =45km/h

• Second bus leave average =40km/h

Let the time = x

T =45 × t + 40 × t = 225

⇒ 85t = 225

⇒ T=3 hour

So,

1:00 PM + 3 hour = 4 : 00 PM

Distance = time×speed

D = 3×45

= 135

Therefore,

They will cross 135 km away from Anandpur at 4:00 pm.

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