At 20 degree celcius the ag ion concentration in a saturated solution
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interrogate the solubility equilibrium:
A
g
2
C
r
O
4
(
s
)
⇌
2
A
g
+
+
C
r
O
2
−
4
Explanation:
Now we have
K
sp
=
[
A
g
+
]
2
[
C
r
O
2
−
4
]
, and if we call the solubility of
silver chromate
under the given conditions
S
, then, by the given stoichiometry, we write..........
K
sp
=
(
2
S
)
2
×
S
=
4
S
3
And thus
S
=
3
√
1.9
×
10
−
12
4
=
7.80
×
10
−
5
⋅
m
o
l
⋅
L
−
1
.
And thus
S
A
g
+
=
15.6
×
10
−
5
⋅
m
o
l
⋅
L
−
1
;
S
C
r
O
2
−
4
=
7.80
×
10
−
5
⋅
m
o
l
⋅
L
−
1
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