☛ At 20bar, 200 ml ethanol is present in 2lt. container at 400k. Calculate boiling point of ethanol.
Answers
Answered by
6
SOLUTION........
V1 = 200ml.
V2 = 2000ml.
T1 = 400K
T2 = ?
Therefore,
V1 ÷ V2 = T1 ÷ T2
200 / 400 = 2000 / T2.
T2 = 4000K
Hence, Boiling Point will be 4000K.
Hope this will help you..........
V1 = 200ml.
V2 = 2000ml.
T1 = 400K
T2 = ?
Therefore,
V1 ÷ V2 = T1 ÷ T2
200 / 400 = 2000 / T2.
T2 = 4000K
Hence, Boiling Point will be 4000K.
Hope this will help you..........
Answered by
2
Hey mate....
here's ur answer....
V1 = 200ml.......... V2 = 2000ml.
T1 = 400K ............ T2 = ?
V1 ÷ V2
= T1 ÷ T2
200 / 400
= 2000 / T2.
T2 =
4000K
Hope it helps ❤️
here's ur answer....
V1 = 200ml.......... V2 = 2000ml.
T1 = 400K ............ T2 = ?
V1 ÷ V2
= T1 ÷ T2
200 / 400
= 2000 / T2.
T2 =
4000K
Hope it helps ❤️
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