Question

At 25 c the dissociation constant of acid and base oh are same, the ph of 0.01 solutuon ha

Answer 1

Explanation:

Dissociation constant of base (Kb) = 2×10⁻³

To find :

Dissociation constant of its conjugate acid

Solution :

We know that Ka × Kb = Kw

Ka × Kb = 10⁻¹⁴ [Kw = 10⁻¹⁴]

Ka × 2×10⁻³ = 10⁻¹⁴

Ka = 10⁻¹⁴ / (2×10⁻³)

Ka = 5×10⁻¹²

The value of dissociation constant of conjugate acid is 5×10⁻¹²

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