Question

at 25 degree Celsius distance between two electrons in a conductivity cell is 1 cm and each electrode is of 2 cm square cross-section. this conductivity cell filled up with a solution containing 50 gram kcl per litre shows cell resistance 7.25 ohm. what is equivalent conductance of that solution?​

Answer 1

Answer:

Cell constant =Conductance of KClSp. cond. of KCl

=1/250.22.768×10−3

=2.768×10−3×250.2

For 0.01 M CuSO4 solution

Sp.conductivity=Cell constant×Conductance

=2.768×10−3×250.2×83311

Molar conductance =Sp.cond.×C1000

=83312.768×10−3×250.2×1/1001000=8.312 ohm−1cm2mol−1

Answer 2

Explanation:

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