Question

At 25 degree celsius the equilbrium constant K1 and K2 of two reactions are 2NH3= N2+3H2; K1, 1/2N2+3/2 H2= NH3; K2 The relation between K1 and K2 is​

Answer 1

Answer:

K2 = (1/K1)½

Explanation:

2NH3 = N2+3H2 ; K1

Reverse the reaction

i.e. 3H2+N2 = 2NH3 ; 1/K1

Multiply above reaction by 1/2

Required reaction is

1/2N2+3/3H2 = NH ; (1/K1)½

Therefore, K2 = (1/K1)½