Question

At 25℃ what will be the solubility of silver carbonate in 0.1 m na2co3

Answer 1

Let x = solubility in moles/L.

Ag2CO3 ==> 2Ag^+ + CO3^2-

...x.......2x.......x

.........Na2CO3 ==> 2Na^+ + CO3^2-

initial...0.1M........0.......0

equil.......0........0.2M.....0.1M

Ksp Ag2CO3 = (Ag^+)^2(CO3^2-)

Substitute into Ksp as follows:

Ksp = look in your text for this value.

(Ag^+) = x

(CO3^2-) =2x from Ag2CO3 and 0.1M from Na2CO3 for total of (2x+0.1) and solve for x. The answer will be in M or moles/L. Convert to grams by grams = moles x molar mass and that will be grams/L.