Chemistry, asked by shivani7318, 1 day ago

At 25°C, calculate equilibrium constant for the cell reaction, X(S) + Y+2 (aq)  Y(S) + X2 + (aq) Given : 2 o x / x E  = –1.36 volt ; 2 o y / y E  = –0.76 volt 2.303RT F = 0.06.

Answers

Answered by prasadgode1981
0

Answer:

We know that, logKc=nE∘cell0.0591

Ecell=[ECathode−EAnode]

=[(+0.34V)−(−0.76V)]=1.10V,n=2,

∴logc=2×(1.10V)(0.0591V)=37.29

Kc=Antilog37.29=1.95×1037

Related Videos

Similar questions