At 25°C, calculate equilibrium constant for the cell reaction, X(S) + Y+2 (aq) Y(S) + X2 + (aq) Given : 2 o x / x E = –1.36 volt ; 2 o y / y E = –0.76 volt 2.303RT F = 0.06.
Answers
Answered by
0
Answer:
We know that, logKc=nE∘cell0.0591
Ecell=[ECathode−EAnode]
=[(+0.34V)−(−0.76V)]=1.10V,n=2,
∴logc=2×(1.10V)(0.0591V)=37.29
Kc=Antilog37.29=1.95×1037
Related Videos
Similar questions