At 25°C the saturated vapour pressure of water is 3.165 kPa (23.75 mm Hg). Find the saturated vapour pressure of a 5% aqueous solution of urea (carbamide) at the same temperature. (Molar mass of urea = 60.05 g mol–1).
No irrelevant answers plzz...☺️
Answers
Answered by
2
Answer:
hope it helps you
please mark me as brainlist and please follow me and votes on my all answers
Attachments:
Answered by
3
Explanation:
Let us consider the problem:
Given that:
W=5g,W
A
=95g,M
B
=60.05gmol
−1
M
A
=18gmol
−1
,P
0
A
=3.165kPa
Putting the values in expression
P
A
o
P
A
o
−P
=
M
B
×W
A
W
B
×M
A
3.165kPa
3.165kPa−P
=
60.05gmol
−1
×95g
5g×18gmol
−1
=0.015
Hence,
P=3.165kPa−0.015×3.165kPa
P=3.118kPa.
♥️
Similar questions