Question

at 273 Kelvin temperature and 9 ATM pressure the compressibility for a gas is 0.9 the volume of 1 mole of a gas at this temperature and pressure is​

Answer 1

Explanation:

we know z=pv real/ pv ideal so pv/nRt= 0.9 where v is volume of 1 mole so

9*v/1*0.0821*273 =0.9 thus v= 2.24litre

Answer 2

Answer:

2.24 litre.

Explanation:

From the question we get that the value of compressibility or z is given that 0.9. Since, we know that the we know that the formulae of pv= nrt where p is the pressure, v is the required volume, n is the number of moles, t is temperature.

So, 9*v/1*0.0821*273 =0.9 which on solving we will get the value of volume as v= 2.24litre.