Question

. At 273°C and 380 torr pressure, the density of a gas is 1.25kg/m². So its density at STP in g/l is
​

Answer 1

Answer:

2.29 g / L

Explanation:

Given :

Temperature T₁ = 273 C = 546 K

Pressure P₁ = 380 torr  = 380 / 760 atm = 0.5 atm

From ideal gas equation we know :

P V = n R T

= > P V = ( m / M ) R T

= > P M = ( m / V ) R T   [ d =  ( m / V ) ]

= > P = d R T

= > P₁ = ( d₁ / M ) × R T₁

= > P₂ = ( d₂ / M ) × R T₂

At STP :

P₂ = 1 atm and T₂ = 298 K

We have to find d₂ :

= > ( 0.5 / 1 ) = [ ( 1.25 / M ) R × 546 ] / [ ( d₂ / M ) R × 298 ]

= > 0.5 = ( 1.25 × 546 ) / ( d₂ × 298 )

= > 298 d₂ = 2 ( 682.5 )

= > 2.29 kg / m³ = 2.29 g / L

Therefore , density at STP in g / l is 2.29 g / L