Chemistry, asked by krishna95071, 7 months ago

At 298 K and constant pressure the heat of formation of C H2(g) and CH (8) is 230 and 85 kJmol-. What will be enthalpy change for the
reaction ?
3C2H2(g) → C6H.(g)​

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Answered by varun200406
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11th

Chemistry

Thermodynamics

Enthalpy Change of a Reaction

If the heats of formation o...

CHEMISTRY

If the heats of formation of C

2

H

2

and C

6

H

6

are 230 KJ mol

−1

and 85 KJ mol

−1

respectively, the

ΔH value for the trimerisation of C

2

H

2

is:

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ANSWER

(i) 2C(s)+H

2

(g)→C

2

H

2

(ii) 6C(s)+3H

2

(g)→C

6

H

6

ΔH=85KJ

(iii) C

2

H

2

→2C(s)+H

2

(g)ΔH=−230KJ

(ii) + 3(iii) gives

3C

2

H

2

→C

6

H

6

ΔH=−230×3+85

=−690+85

=−605KJ

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