At 30∘C,Kp30∘C,Kp for the dissociation reaction SO2Cl2(g)⇌SO2(g)+Cl2SO2Cl2(g)⇌SO2(g)+Cl2 is 2.9×10−22.9×10−2 atm. If the total pressure is 1 atm, the degree of dissociation of SO2Cl2SO2Cl2 is (assume, 1−α2=11−α2=1)
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Answer:
83%
Explanation:
SO2Cl2 = SO2 + Cl2
1 0 0
At equilibrium 1-x x x
mole fraction 1+x 1+x 1+x
kp = SO2 X Cl2
SO2Cl2
kp = x/1+x .P x/1+x. P
1-x/1+x .P
After simplication,
kp = x2
1 – x2 ( Here 1 – x2 =1, it is given),
so equatiion turns into kp = x2
substitute the value of kp= 2.9 x 10-2 , then x = 1.7 X 10-1 or 17%.
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