Chemistry, asked by tanyasinghal55861, 10 months ago

At 30∘C,Kp30∘C,Kp for the dissociation reaction SO2Cl2(g)⇌SO2(g)+Cl2SO2Cl2(g)⇌SO2(g)+Cl2 is 2.9×10−22.9×10−2 atm. If the total pressure is 1 atm, the degree of dissociation of SO2Cl2SO2Cl2 is (assume, 1−α2=11−α2=1)

Answers

Answered by vishalbajpai3103
8

Answer:

83%

Explanation:

            SO2Cl2 = SO2 + Cl2

                            1          0         0

At equilibrium        1-x       x         x

mole fraction         1+x    1+x     1+x

 

        kp = SO2 X  Cl2

                  SO2Cl2

        kp =   x/1+x .P   x/1+x. P

                        1-x/1+x .P

After simplication,

       kp =  x2

             1 – x2        ( Here 1 – x2 =1, it is given),  

 

so equatiion turns into kp = x2

 

substitute the value of kp= 2.9 x 10-2 , then x = 1.7 X 10-1   or 17%.

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