Question

At 300 K, the density of a certain gaseous molecule at 2 bar is double to that of dinitrogen at 4 bar. The molar mass of the gaseous molecule is
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Answer 1

Answer:

P1V1=nRT

P2V2=n'RT

n=dV1/M1 (d=density) ..............(1)

n'=d'V2/28

d=2*d'

(1) becomes

n=2*d'V1/M1;

P1V1=(2*d'V1/M1)*RT .................(2)   {V1 gets cancelled}

P2V2=(d'V2/28)*RT.......................(3)   {V2 gets cancelled}

taking  (2)/(3):

P1/P2=(2/M1)/(1/28)

->2/4=56/M1

->M1=112g mol^(-1)