Question

at 30°c 7g common salt dissolved in 20g water to prepare a saturated solution find the solubility of salt at 30°c​

Answer 1

Answer:

Explanation:

weight of salt = 90 gram,  

solubility  = 50

sing formula  

solubility of solute =  

weightofsolventinsaturatedsolution

weightofsoluteinsaturatedsolution

​  

×100

or 50=  

weightofsolventinsaturatedsolutio

90gm

​  

×100

so weight of solvent in saturated solution =  

50

90gm

​  

×100=180gm

Hence 180 gm of water is required to prepare a saturated solution.

Answer 2

Explanation:

Weight of a Salt=90 gram,

Solubility=50

Solubility of a salt in a saturated solution/ weight of a salt in saturated solution×100

or

50= weight of the salt in saturated solution/90 gram×100

So, weight of a salt in saturated solution=50/90×100=180 gram

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