Question

x² - √2x - 4 = 0 ; -2 , 2√2

Answer 1

x²-√2x -4

=> x ²- 2√2x + √2x -4

=> x( x - 2√2 ) + √2 ( x - 2√2 )

=> ( x + 2√2 ). ( x - 2√2 )

x + 2√2 => 0. x - 2√2 = 0

x = 0 -2√2. x = 0 + 2√2

x => -2√2 x = 2√2

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RULES TO FACTORIZE .....

(1) FIRST MULTIPLY THE 1ST FIGURE WITH LAST FIGURE ...

MEANS x² * -4 => -4x²

(2) AFTER THAT , SPLIT THE MIDDLE NUMBER IN TWO PARTS SO THAT MULTIPLE OF TWO NUMBER WILL BE EQUAL TO -4x² or ADD / SUBTRACTION OF TWO NUMBERS WILL EQUAL TO - √2 x

(3) THEN FIND COMMON WITH FIRST TWO NUMBER AND LAST TWO NUMBERS

(4) MAKE FACTORS BY NUMBERS EQUAL TO ZERO .

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Answer 2

Answer:

x² - √2x - 4 = 0

Let, x = -√2

x² - √2x - 4 = 0

(-√2)² -√2.-√2 -4 = 0

2 + 2 - 4 = 0

4 - 4 = 0

0 = 0

Thus, -√2 is the root of given equation

Let, x = 2√2

x² - √2x - 4 = 0

(2√2)² - √2.2√2 - 4 = 0

4.2 - 2.2 - 4 = 0

8 - 4 - 4 = 0

8 - 8 = 0

0 = 0

Thus, 2√2 is the root of given equation