Question

At 300k a certain mass of gas occupies 3.3×10 -4 dm3 volume calculate its volume at 665 k and the same pressure

Answer 1

pv=nrt

since no. of moles and pressure are constant,

v1/t1=v2/t2

v1=3.3*10^-4 dm3

v2=?

t1=300k

t2=665k

putting values in equation,

3.3*10^-4/300=v2/665

=>v2=0.00073dm3 OR 7.3*10^-4 dm3 OR 7.3*10^-4 litres