Question

at 300k the vapour pressure of a substance a is 0.95atm and vapour pressure of substance b is 0.15atm a solution of a and b is prepared and allowed to equilibrate with its vapour the vapour is found to have equal moles of a and b what is the mole fraction of a in the original solution
a)0.18
b)0.14
c)0.23
d)0.34​

Answer 1

Answer:

c. is your answer

Explanation:

Hope it helps you

Answer 2

Answer:

b 0.14

Explanation:

(Pressure of A)(moles of A)=(pressure of B)(moles of B)

P°a(x)=P°b(1-x)

0.95(x)=0.15(1-x)

0.95x=0.15-0.15x

1.1x=0.15

therefore,

x=0.15/1.1=0.136

therefore,

x is approximately equal to 0.14