At 4*C, 0.98 of the volume of a body is immersed in water. The temperature at which the entire body gets immersed in water is ( neglect the exoansion of the body) ( gama of water= 3.3 x 10^-4 k^-1)
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45
Hey dear,
# Answer- 64.6°C.
# Explanation-
Volumetric Temperature Coefficient is given by formula
γ = Δ V/ΔT
For complete immersion of body
Δ V = 1-0.98 = 0.02 units
ΔT = Δ V/ γ
ΔT = (0.02)/(3.3×10^-4)
ΔT = 60.6 °C
T2-T1 = 60.6
T2 = 60.6+4
T2 = 64.6 °C
The body will completely sink at temperature 64.6°C.
Hope this is useful.
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Answered by
7
Dear Student,
Considering,
Volumetric Temperature Coefficients: 3.3×10−4/K.(change in volume per unit change in temperature)
at 4 deg celcius 0.98 of volume is immersed so to immerse completly in the liquid we will need to raise the temperature of water.
for 10K ⇒3.3×10−4unit volume increases.now for complete immerson of liquid we need to raise the volume of liquid by 0.02so,T=0.023.3×10−4T=60.6 C
Regards
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Considering,
Volumetric Temperature Coefficients: 3.3×10−4/K.(change in volume per unit change in temperature)
at 4 deg celcius 0.98 of volume is immersed so to immerse completly in the liquid we will need to raise the temperature of water.
for 10K ⇒3.3×10−4unit volume increases.now for complete immerson of liquid we need to raise the volume of liquid by 0.02so,T=0.023.3×10−4T=60.6 C
Regards
Was this answer helpful
5
Popular questions from Thermal Properties Of Matter
relation between alpha/beta and gamma
a body cools down from 45 C to 40 C in 5 minutes and to 35 C in another 8 min...
Question number 7th
Why do you think this post is offensive?
It has foul language
It is irrelevant
Any other
SUBMIT
Ask question
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