at 40 degree Celsius hydrogen is equal to Hydroxide ion but the values are are more than 10 ki power minus 7 Mol per DM cube and pure water it again neutral at 40 degrees celsius kindly ko is sentence ko elaborate kar de means Iske concept ko matlab values modern 10 ki power minus 7 Mol per DM cube Kaise Hogi thank you I want correct answer please otherwise you are responsible for it
Answers
Explanation:
As discussed earlier, hydronium and hydroxide ions are present both in pure water and in all aqueous solutions, and their concentrations are inversely proportional as determined by the ion product of water (Kw). The concentrations of these ions in a solution are often critical determinants of the solution’s properties and the chemical behaviors of its other solutes, and specific vocabulary has been developed to describe these concentrations in relative terms. A solution is neutral if it contains equal concentrations of hydronium and hydroxide ions; acidic if it contains a greater concentration of hydronium ions than hydroxide ions; and basic if it contains a lesser concentration of hydronium ions than hydroxide ions.
A common means of expressing quantities, the values of which may span many orders of magnitude, is to use a logarithmic scale. One such scale that is very popular for chemical concentrations and equilibrium constants is based on the p-function, defined as shown where “X” is the quantity of interest and “log” is the base-10 logarithm:
pX = −log X
The pH of a solution is therefore defined as shown here, where [H3O+] is the molar concentration of hydronium ion in the solution:
pH = −log[H3O+]
Rearranging this equation to isolate the hydronium ion molarity yields the equivalent expression:
[H3O+] = 10−pH
Likewise, the hydroxide ion molarity may be expressed as a p-function, or pOH:
pOH = −log[OH−]
or
[OH−] = 10−pOH
Finally, the relation between these two ion concentration expressed as p-functions is easily derived from the Kw expression:
Kw = [H3O+][OH−]
−logKw = −log([H3O+][OH−]) = −log[H3O+] + −log[OH−]
pKw = pH + pOH
At 25 °C, the value of Kw is 1.0 × 10−14, and so:
14.00 = pH +pOH
As we learned earlier, the hydronium ion molarity in pure water (or any neutral solution) is 1.0 × 10−7 M at 25 °C. The pH and pOH of a neutral solution at this temperature are therefore:
pH = −log[H3O+] = −log(1.0 × 10−7) = 7.00
pOH = −log[OH−] = −log(1.0 × 10−7) = 7.00
And so, at this temperature, acidic solutions are those with hydronium ion molarities greater than 1.0 × 10−7 M and hydroxide ion molarities less than 1.0 × 10−7 M (corresponding to pH values less than 7.00 and pOH values greater than 7.00). Basic solutions are those with hydronium ion molarities less than 1.0 × 10−7 M and hydroxide ion molarities greater than 1.0 × 10−7 M (corresponding to pH values greater than 7.00 and pOH values less than 7.00).
Since the autoionization constant Kw is temperature dependent, these correlations between pH values and the acidic/neutral/basic adjectives will be different at temperatures other than 25 °C. For example, the hydronium molarity of pure water is 80 °C is 4.9 × 10−7 M, which corresponds to pH and pOH values of:
pH = −log[H3O+] = −log(4.9 × 10−7) = 6.31
pOH = −log[OH−] = −log(4.9 × 10−7) = 6.31
At this temperature, then, neutral solutions exhibit pH = pOH = 6.31, acidic solutions exhibit pH less than 6.31 and pOH greater than 6.31, whereas basic solutions exhibit pH greater than 6.31 and pOH less than 6.31. This distinction can be important when studying certain processes that occur at nonstandard temperatures, such as enzyme reactions in warm-blooded organisms. Unless otherwise noted, references to pH values are presumed to be those at standard temperature (25 °C) (Table 1).