Question

at 400k temperature And 0.0821 atm the density of co2 is (g/lit)
0.01
0.11
2.5
4.4​

Answer 1

Answer:

don’t know how close CO2 is to an ideal gas but if that’s a safe assumption we want to use the Ideal Gas Law:

Pv=RT

Where

P is the pressure in Pascals

v is the specific volume which is the reciprocal of the density

R is the specific gas constant for CO2

and

T is the absolute temperature in deg K

v=RT/P

From www.engineeringtoolbox.com,

for CO2, R= 0.189 kJ/kg-K

From any units converter app, 0.0821 atm = 8419 Pa.

We can now calculate the specific volume

v=(0.189 kJ/kg-K)(400K)/(8319 Pa)

9.08E-03 cubic meters/kg

The density is the reciprocal of this

110 kg/cubic meter.

hope that helps

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Answer 2

The density is 0.11 g/lit.

Given - Temperature and pressure

Find - Density

Solution - Using ideal gas equation to find the density.

Pressure*Volume = Mass*Gas constant*Temperature/molar mass

Mass/ Volume = P*M/R*T

Taking R as 0.082 L atm/mol/K

Keep the values in formula

Density = $\frac{0.0821 \times 44}{0.082 \times 400}$

Performing multiplication and division

Density = 0.11 g/lit

Hence, the density of CO2 is 0.11 g/lit.

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