At 60°,dinitrogen tetraoxide is 60% dissociated. Calculate the standard free energy change at this temperature and one atmosphere.
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The total pressure at equilibrium = 1atm
Let the number of moles at the beginning of N2O4 be 1.
At 60% dissociation, the amount of N2O4 remaining = 0.6
At this point, number of NO2 = 1
Total number of moles = 1.6
Partial pressure of NO2 = 1/1.6 x1 = 0.625
Partial pressure of N2O4 = 0.3125
So, the Kp = [NO2]2 / [N2O4] = 0.66 x 0.66 / 0.3125 = 1.39392 atm
Let the number of moles at the beginning of N2O4 be 1.
At 60% dissociation, the amount of N2O4 remaining = 0.6
At this point, number of NO2 = 1
Total number of moles = 1.6
Partial pressure of NO2 = 1/1.6 x1 = 0.625
Partial pressure of N2O4 = 0.3125
So, the Kp = [NO2]2 / [N2O4] = 0.66 x 0.66 / 0.3125 = 1.39392 atm
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