Question

At 700k the equilibrium
const kc for the chemical
reaction 2so3 reversable2so2 +o2 is 1.8 pascal what
is the kp value !​

Answer 1

Answer:

Kp = Kc (RT) ∆n

Kc = Kp / (RT) ∆n

T = 700 K

R = 8.314 J mol -1 K-1

∆n = (2 + 1) – 2 = 1

Kp = 1.8 X 10-3 kPa = 1.8 Pa

Therefore,

Kc = 1.8 Pa / (8.314 J mol -1 K-1) (700)1

= 3.09 X 10-7 mol m-3

Hence, the numerical value in moles per liter of Kc is equal to 3.09 X 10-7 mol m-3

Explanation:

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