Question

at 700K,the equilibrium constant KP for the reaction 2SO3[g]<---->2SO is 1.8*10-3kPa.what is the value of KC for the same temperature?​ please give meaningful step by step answers,not any similar link.

Answer 1

Answer:

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Explanation:

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Answer 2

Answer:

3.1 × 10^-5

Explanation:

By the formula Kp = Kc(RT)^An

So,

Delta n = 1 ( from equation given in the que)

so,

1.8 × 10^-3 = Kc(8.31×700)^1

Kc = 3 × 10^-7 ~ 3.1 × 10^-5