At a birthday party every child gets 2 chocolates every mother gets 1 chocolate while no father gets chocolate. In total 69 persons gets 70 chocolates. If the no of children is half of the no of fathers and mothers put together then How many fathers are there?
Answers
Answer:
Step-by-step explanation:
Let number of children = x
Total of Father+ Mother count = 2x
Total person = 3x
3x = 69 person
x= 69/3 = 23
Thus there are 23 children and they get 46 chocolates.
Now Total of Father and Mother = 2x = 46
Remaining chocolates = 70-46 = 24.
Since Fathers are not given any chocolates mothers get one chocolate each there are 24 mothers.
Total children = 23
Total mother 24
Number of fathers = 70 - 47 (total of children and mother's count) = 23
Answer:
22 fathers
Step-by-step explanation:
Given:
Each child gets 2 Chocolate
Mother gets 1 Chocolate
Father gets no Chocolate
Total persons = 69
Total chocolates = 70
Total children = half of (mother + father)
Solution:
Let number of children = x
Then
Total of Father+ Mother = 2x
Total person = x+2x=3x
As total persons there are 69 so
3x = 69 person
x= = 23 children
Total Chocolate children will get = 23 * 2 = 46 chocolates
Thus there are 23 children and they get 46 chocolates.
Now Total of Father and Mother = 2x = 46
Remaining chocolates = 70-46 = 24.
Since Fathers are not given any chocolates mothers get one chocolate each there are 24 mothers.
Total children = 23
Total mother =24
Number of fathers = 69 - (total of children and mother's count)
=69 - (47)
=22
So there are 22 fathers