Math, asked by student5050, 5 months ago

at a breakfast buffet,93 people chose coffe and 47 chose juice,25 people chose both coffee and juice,if each person chose at least one of these beverage,how many people visited the buffet ​

Answers

Answered by srk12092khan
14

the answer is 115

coffee = 93

juice = 47

both coffee and juice = 25

only coffee = 93-25 = 68

only juice = 47 - 25 = 22

Total people may visit = 68+22+25=115

Answered by TheWiseStudent
1

Answer:

115 people visited the buffet.

Step-by-step explanation:

Given:

  • At a breakfast buffet,93 people have chosen coffee, 47 have chosen juice and 25 people have chosen both coffee and juice.
  • Also,each person chosen at least one of these beverage

Need To Find:

How many people have visited the buffet

Solution:

According to question,

Number of people who have chosen coffee = n(C) = 93

Number of people who have chosen juice = n(J) = 47

Number of people who chosen both coffee and juice = n(C∩J) = 25

Now as we know,

n(A∪B) = n(A) + n(B) - n(A∩B)

Now as per question,

Each person has chosen at least one of these beverage

Therefore, using the above formula to find number of people who have visited the buffet

n(C∪J) = n(C) + n(J) - n(C∩J)

n(C∪J) = 93 + 47 -25

n(C∪J) = 115

Hence, 115 people visited the buffet.

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