At a car park there are 100 vehicles,60 of which are cars,30 are vans and the remainders are lorries. If every vehicle is equally likely to leave, find the probability of a car leaving second if either a lorry or van had left first
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Total vehicles = 100 (Given)
Total cars = 60 (Given)
Total van = 30 (Given)
Total lorries = 100 - 60 - 30 = 10
P(Second vehicle is a car) = P(1st vehicle is a Lorry/van) x P(2nd vehicle is a car)
P(Second vehicle is a car) = (30 + 10)/100 x 60/(100 - 1)
P(Second vehicle is a car) = 8/33
If you need the answer in percentage:
8/33 x 100 = 24.24%
Answer: The probability of a car leaving second is 8/33
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