Question

At a certain height above the Earth's surface, the acceleration due to gravity is 4% of its value at the surface of the earth. Determine the height.

Answer 1

we know, acceleration due to gravity at a height h from earth's surface is given by , $g=\frac{g_0}{\left(1+\frac{h}{R}\right)^2}$

where $g_0$ is the acceleration due to gravity at earth's surface, h is height from the earth's surface and R is the radius of the earth surface.

A/c to question,
g = 4 % of $g_0$

So, 4$g_0$/100 = $g_0$/(1 + h/R)²

or, 4/100 = 1/(1 + h/R)²

or, 10/2 = (1 + h/R)

or, 4R = h

we know, R = 6400km (approximately)

so, h = 4 × 6400 = 25,600 km

Answer 2

Answer:

hi

Explanation:

h = 4R.

hope you get it.

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