Question

At a certain temperatur, 3.24 moles of CO2 gas at 2.15 atmtake up a volume of 35.28L. What is this temperature ( in celcius)?????​

Answer 1

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Answer 2

Answer:

The temperature of the gas in Celsius, T, calculated is $12.35\textdegree C$.

Explanation:

Given data,

The number of moles of $CO_{2}$ gas, n = $3.24$ mol

The pressure of the gas, P = $2.15atm$

The volume take-up by the $CO_{2}$ gas, V = $35.28L$

The temperature of the gas in Celsius, T =?

Now, by using the ideal gas equation, we can find out the temperature of the gas:

• $PV =nRT$

Here, R = Gas constant = $0.082L-atm/K-mol$

After substituting the given values of moles, pressure, and volume in the above mentioned ideal gas equation, we get:

• $2.15\times 35.28 = 3.24\times 0.082\times T$
• T = $\frac{75.852}{0.2656}$ = $285.5K$

Now, we have to convert Kelvin into Celsius:

• $\textdegree C = K - 273.15$

Thus,

• T = $(285.5 - 273.15)\textdegree C$ = $12.35\textdegree C$

Hence, the temperature of the gas in Celsius, T = $12.35\textdegree C$.