At a certain temperature and pressure 100ml of carbon dioxide diffuses in some time. In the same time volume of N^2O diffused in ml is
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use Graham ' law of diffusion
let v1 is volume of CO2 , and V2 is volume of N2O then ,
time is same so,
V1 /V2 =√M2/M1
here M2 is molar mass of N2O and M1 is n
molar mass of CO2
then ,
100/V2 = √( 44/44) = 1
V2 = 100
hence, volume of N2O is same as volume of CO2
let v1 is volume of CO2 , and V2 is volume of N2O then ,
time is same so,
V1 /V2 =√M2/M1
here M2 is molar mass of N2O and M1 is n
molar mass of CO2
then ,
100/V2 = √( 44/44) = 1
V2 = 100
hence, volume of N2O is same as volume of CO2
cvrohit:
Thanks Abhi
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