Chemistry, asked by sagarsrishti, 6 months ago

.. At a certain temperature, pure water has
[H,0+) =10^6.7 mol L-' .What is the value of Kw at
this temperature :-

Answers

Answered by adithyananil3507
1

Answer:

10  −6.7 ×10−6.7 =10−13.4

Explanation:

In pure water, [H  

3

​  

O  

+

]=[OH  

]

K  

w

​  

=[H  

3

​  

O  

+

][OH  

]

As given, [H  

3

​  

O  

+

]=10  

−6.7

mol/lit

So, K  

w

​  

=10  

−6.7

×10  

−6.7

=10  

−13.4

Similar questions