Question

At a certain temperature, the r.m.s. velocity
for 02 is 400 m/sec. At the same temperature,
the r.m.s velocity for H2 molecules will be

1) 100 m/sec

2) 25 m/sec

3)1600 m/sec

4) 6400 m/sec​

Answer 1

Answer:

Explanation:

Solution,

Here, we have

r.m.s of O₂ = 400 m/s

To Find,

r.m.s of H₂

Here, we know that,

⇒ C = √3RT/m

⇒ CO₂ = √3RT/MO₂ ....... (i)

Now, For H₂

⇒ CH₂ = √3RT/mH₂ ........(ii)

Now, dividing both the eq, we get

CO₂/CH₂ = √mH₂/mO₂

⇒ CH₂ = CO₂/√mH₂/mO₂

⇒ CH₂ = 400/√2/32

⇒ CH₂ = 400 × 4

⇒ CH₂ = 1600 m/s.

Hence, the r.m.s velocity of H₂ is 1600 m/s.

Here, third option i.e 1600 m/s is correct.

Answer 2

Answer:

3) 1600 m/sec

Explanation:

Here,

Vo2 = 400 m/sec

Mass of O2 ( Mo2) = 32

Mass of H2 ( MH2) = 2

Ur.m.s = √(3RT/M)

=> VH2/Vo2 =√(Mo2/MH2)

=> VH2 = 400 × √(32/2)

= 400 × √16

= 400 × 4

= 1600 m/s Ans...