Specific conductivity of 0.01 N H 50solution is 6 * 10-3 Scm-1. Its molar conductivity is
(1) 1200 Scm2 mol-1
(2) 600 Scmmol-1
(3) 60 Scm2 mol-1
(4) 2400 Scm² mol-1
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The relationship between specific conductivity (K) and molar conductivity
Ʌm is as follows.
Ʌm= K/c
Here c is the concentration in terms of molarity.
First of all we should find molarity. To do this multiply no. of replacable hydrogens with normality i.e. 0.01/2=0.005M
Now apply formula:
Ʌm=6×10-3/0.005=1.2 Scm-1M-1
Now to convert the units to Scm-2mol-1 multiply with 1000, the answer is 1200
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