Question

At a certain temperature, the vapour pressure of water is 50 mm .The relative lowering of vapour pres
sure of a solution containing 36 g of glucose in 900 g of water is
a) 0.1
b) 0.5
c) 0,004
d) 3.75​

Answer 1

Answer:

The lowering of vapor pressure is 0.004

Explanation:

The relative lowering of vapor pressure is a colligative property.

The relation between relative lowering of vapor pressure and mole fraction of solute is:

Relative lowering of vapor pressure = mole fraction of solute

the solute is glucose

moles = mass / molarmass

let us calculate the moles of both solute and solvent

moles of solute = 36 / 180 =0.2

moles of water = 900 / 18 = 50

total moles =50.2

mole fraction of glucose = 0.2/50.2=0.004

thus the lowering of vapor pressure is 0.004

Answer 2

Answer:

option c is correct

Explanation:

(c) 0,004