Question

At a certain time in a deer park the number of heads and the number of legs of deer and human visitors were counted and it was found that there were 39 heads and 132 legs. find the number of deer andhu!an visitors in the park

Answer 1

Let the number of deer in the park be x and human visitors be y
As each deer and each human has one head
x+y =39 ... (1)
As each deer has four legs and each human has two legs
4x+2y =132
2x+ y = 66 ...(2)
Subtract equation (1) form equation (2) , we get
x =27
put the value of x in equation (1), we get
27+y =39
y = 39 -27
y= 12
Hence , there are 12 visitors and 27 deer.

Answer 2

Let the number of deer in the park be x and human visitors be y
As each deer and each human has one head.
x + y = 39... (1)
As each deer has four legs and each human has two legs.
4x + 2y = 66... (2)
Subtract equation (1) from equation (2), we get
x = 27
Put the value of x in equation (1), we get 27 + y = 39
y = 39-27
Y = 12
Hence, There are 12 visitors and 27 deers.