At a certain time in a deer park, the number of heads and the number of legs of deer and human visitors were counted and it was found there were 39 heads & 132 legs. Find the number of deer and human visitors in the park.
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let x be the total no of legs of deer
let y be the total no of legs of visitors.
∴x + y = 132
∵1deer has 4 legs and 1 head & 1 visitor has 2 legs and 1 head
∴x/4 + y/2 = 39
plotting the graph we get the point of intersection which is the value of x and y.
thus from the graph we can say x = 108 and y=24
∴ num of deers = 108/4 = 27
∴ num of visitors = 24/2 = 12
let y be the total no of legs of visitors.
∴x + y = 132
∵1deer has 4 legs and 1 head & 1 visitor has 2 legs and 1 head
∴x/4 + y/2 = 39
plotting the graph we get the point of intersection which is the value of x and y.
thus from the graph we can say x = 108 and y=24
∴ num of deers = 108/4 = 27
∴ num of visitors = 24/2 = 12
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Answer:let tiger be =deers
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