Math, asked by divyansh130, 1 year ago

At a certain time in a zoo , the number of heads and legs of tigers and peacocks wre counted. It was found that there were 47 hrads and 152 legs.Find the number of tigers and peacocks in the zoo .

Answers

Answered by sadiyaj05
64

Answer: No. of tigers 29 and peacocks 18.

Step-by-step explanation:

Let the number of tigers be t and that of peacocks be p,

Then head count :

t+p =47 _____eq 1

Leg count :

4t+2p =152 _____eq 2

Solving eq 1 and eq 2 we get, t= 29

Substituting t =29 in eq 1, we get p = 18.

Therefore the number of tigers is 29 and peacocks is 18.

Answered by visala21sl
19

Answer:

The variety of tigers is 29 and peacocks is 18.

Step-by-step explanation:

Let the variety of tigers be T and that of peacocks be P,

Then head count :

T + P =47 ----------(1)

Leg count :

4T+2P =152 ----------------(2)

Solving equation(1) and equation(2)

we get, T = 29

Substituting T =29 in equation(1),

we get P = 18.

Therefore, the variety of tigers is 29 and peacocks is 18.

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