At a constant temperature a gas is initially at 2 atmosphere pressure. To compress to to 1/8 of its initial volume. pressure to be applied is
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Answered by
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We can use Boyle's Law
P1V1=P2V
2
to solve for the pressure since the temperature is being held constant.
For this case we are going to use
8L to represent the original volume and 1L to represent the 1/8 value of the final volume.
P1=2atm
V1=8L
P2=?
V2=1L
(2atm)(8L) = (P2)(1L)
(2atm)(8L)/1L= (P2)(1L)/1L
16atm=P2
P1V1=P2V
2
to solve for the pressure since the temperature is being held constant.
For this case we are going to use
8L to represent the original volume and 1L to represent the 1/8 value of the final volume.
P1=2atm
V1=8L
P2=?
V2=1L
(2atm)(8L) = (P2)(1L)
(2atm)(8L)/1L= (P2)(1L)/1L
16atm=P2
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Answered by
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hlw mate ur ans ❤
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