Question

At a constant temperature, volume of a gas was found to be 400 cm³ at a pressure of 760 mm Hg. If the pressure of the gas is increased by 25%, find the new volume.
(By using Boyle's Law)

ONLY ANSWER NEEDED or else I'll report.​

Answer 1

Given:-

→ Initial volume of the gas = 400cm³

→ Initial pressure = 760 mm

→ New pressure is the initial prrssure

increased by 25%.

To find:-

→ New volume

Solution:-

Firstly, let's calculate the new pressure :-

=> 760 + (25/100 × 760)

=> 760 + 190

=> 950 mm

Now, according to Boyle's Law, we know that:-

If V₁ , be the volume of a given mass of the gas having pressure P₁, at temperature T. Now, if the pressure is change to P₂ , at the same temeprature, and if the volume changes to V₂ , the relationship between P₁ ,V₁ ,P₂ and V₂ is :-

P₁V₁ = P₂V₂ [T and n are constant]

=> 760 × 400 = 950 × V₂

=> 304000 = 950 × V₂

=> V₂ = 304000/950

=> V₂ = 320 cm³

Thus, the new volume is 320cm³ .

Answer 2

Answer:

320 cm³

Explanation:

P1 = 760 mm of Hg

V1 = 400 cm³

P2 = P1 + 25% of P1

V2 = ?

P2 = 760 + 25/100 × 760

P1 = 950 mm of Hg

Putting all values in 1

760×400=950×?

V2=4760×400/9505

V2 = 1600/5

V2=320 cm³