At a constant temperature, volume of a gas was found to be 400 cm³ at a pressure of 760 mm Hg. If the pressure of the gas is increased by 25%, find the new volume.
(By using Boyle's Law)
ONLY ANSWER NEEDED or else I'll report.
Answers
Given:-
→ Initial volume of the gas = 400cm³
→ Initial pressure = 760 mm
→ New pressure is the initial prrssure
increased by 25%.
To find:-
→ New volume
Solution:-
Firstly, let's calculate the new pressure :-
=> 760 + (25/100 × 760)
=> 760 + 190
=> 950 mm
Now, according to Boyle's Law, we know that:-
If V₁ , be the volume of a given mass of the gas having pressure P₁, at temperature T. Now, if the pressure is change to P₂ , at the same temeprature, and if the volume changes to V₂ , the relationship between P₁ ,V₁ ,P₂ and V₂ is :-
P₁V₁ = P₂V₂ [T and n are constant]
=> 760 × 400 = 950 × V₂
=> 304000 = 950 × V₂
=> V₂ = 304000/950
=> V₂ = 320 cm³
Thus, the new volume is 320cm³ .
Answer:
320 cm³
Explanation:
P1 = 760 mm of Hg
V1 = 400 cm³
P2 = P1 + 25% of P1
V2 = ?
P2 = 760 + 25/100 × 760
P1 = 950 mm of Hg
Putting all values in 1
760×400=950×?
V2=4760×400/9505
V2 = 1600/5
V2=320 cm³